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BIOSTATISTICS-Normal Curve, Test of significance, Standard error

BIOSTATISTICS-Normal Curve, Test of significance, Standard error

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Q. 1 If  mean, median and  mode are 10, 18, 26 respectively, the distribution is :
 A Symmetric
 B

Normal

 C

Positively skewed        

 D

Negatively skewed

Q. 2

The systolic blood pressure of 10 individuals was measured. The mean and median values were calculated to be 130 mmHg and 140 mmHg respectively. What is the shape of the frequency distribution curve?

 A

Symmetrical distribution

 B

Bimodal distribution

 C

Positively skewed distribution

 D

Negatively skewed distribution

Q. 3

In a bell-shaped standard normal curve, mean ±2 standard deviations covers:

 A

60%

 B

65%

 C

95%

 D

99%

Q. 4

A normal distribution curve depends on – 

 A

Mean and Sample size

 B

Range and Sample Size

 C

Mean and Standard deviation

 D

Mean and median

Q. 5

Shape of normal distribution curve‑

 A

J shape

 B

U shape

 C

Bell shape

 D

None

Q. 6

Regarding the normal curve, true is/are-

 A

Both limbs of the curve touch the baseline

 B

Curve is bilaterally symmetrical

 C

There is a skew to the right

 D

There is a skew to the left

Q. 7

Normal curve –

 A

Distribution of data is symmetrical

 B

Mean > Mode

 C

Mode > Mean

 D

Median > Mean

Q. 8

Systolic BP of a group of persons follows normal distribution curve. The mean BP is 120. The values above 120 are –

 A

25%

 B

75%

 C

50%

 D

100%

Q. 9

In a group of 100 children, the weight of a child is 15 kg. The standard error is 1.5 kg. Which one of the following is TRUE –

 A

95% of all children weigh between 12 and 18 kg

 B

95% of all children weigh between 13.5 and 16.5 kg

 C

99% of all children weigh between 12 and 18 kg

 D

99% of all children weigh between 13.5 and 16.5kg

Q. 10

Standard error of mean indicates –

 A

Dispersion

 B

Distribution

 C

Variation

 D

a and c

Q. 11

Standard errors of mean, all are true except

 A

Increases with increased number of samples

 B

Based on normal distribution curve

 C

Measure the confidence limit

 D

Standard deviation

Q. 12

While calculating the incubation period for measles in a group of 25 children, deviation is 2 and the mean incubation period is 8 days. Calculate the standard error –

 A

0.4

 B

1

 C

0.5

 D

2

Q. 13

Estimated mean Hemoglobin (I-lb) of 100 women is 10g%. Standard deviation (a) is lgm%. Standard error of estimate will be –

 A

0.001

 B

1.0

 C

10.0

 D

0.1

Q. 14

For a negatively skewed data mean will be

 A

Less than median

 B

More than median

 C

Equal to median

 D

One

Q. 15

In a Left skewed curve, true statement is?

 A

Mean = Median

 B

Mean < Mode

 C

Mean>Mode

 D

Mean = Mode

Q. 16

A non-sysmmetrical frequency distribution is known as –

 A

Normal distribution

 B

Skewed distribution

 C

Cumulative frequency distribution

 D

None of the above

Q. 17

In a normal distribution curve, the true statement is:

March 2011, March 2013

 A

Mean = standard deviation

 B

Median = standard deviation

 C

Mean = 2 median

 D

Mean = mode

Q. 18

The type of distribution, if mean 209, median 196, and mode 135 ‑

 A

Standard curve

 B

Positively skewed

 C

Negatively skewed

 D

J-shaped

Q. 19

In positively skewed deviation ‑

 A

Mean = Median = Mode

 B

Mean > Medians > Mode

 C

Mode > Median > Mean

 D

None of the above

Q. 20

Identify the Distribution Shown.

 A

Normal Distribution

 B

Right Skewed Distribution

 C

Left Skewed Distribution

 D

Poisonn’s Distribution

Q. 21

The following box plot shows the distribution of three sets of data around the mean. What is the correct sequence of inference from this box plot?

 A

1-Normal distribution, 2-Positive skewed, 3-Negative skewed

 B

1-Normal distribution, 2-Negative skewed, 3-Positive skewed

 C

1-Negative skewed, 2-Positive skewed, 3-Normal distribution

 D

I -Positive skewed, 2-Normal distribution, 3-Negative skewed

Q. 22

Area under Normal curve with ±1 SD:

 A

0.68

 B

0.17

 C

0.12

 D

0.34

Q. 1

If  mean, median and  mode are 10, 18, 26 respectively, the distribution is :

 A

Symmetric

 B

Normal

 C

Positively skewed        

 D

Negatively skewed

Ans. D
Explanation:

Negatively skewed

For a symmetric curve such as gaussian – mean, median and mode coincide. That is, they are the same value.

– A skewed distribution will have different mean, median and mode. In fact, very different values of mean, median and mode is a clear indication of skewness.

In positive skew, mean>median>mode. In negative skew, mean<median<mode.


Q. 2

The systolic blood pressure of 10 individuals was measured. The mean and median values were calculated to be 130 mmHg and 140 mmHg respectively. What is the shape of the frequency distribution curve?

 A

Symmetrical distribution

 B

Bimodal distribution

 C

Positively skewed distribution

 D

Negatively skewed distribution

Ans.
D
Explanation:

A negatively skewed distribution is where most of the values are on the higher side and the tail is pointing left.

The mean of a distribution is more affected by extreme values than is the median.

Therefore, in a negatively skewed distribution with few values on the lower end of the distribution, the mean is pulled towards the tail or lower end and becomes less than the median.

Ref: Park’s Textbook Of Preventive And Social Medicine, By K. Park, 19th Edition, Pages 699-702; Essentials of Research Methods in Health, Physical Education, Exercise Science and Recreation, By Kris E. Berg, Richard W. Latin, Second Edition, Pages 85-87; High-Yield Biostatistics, By Anthony N. Glaser, Third Edition, Pages 10, 11.


Q. 3

In a bell-shaped standard normal curve, mean ±2 standard deviations covers:

 A

60%

 B

65%

 C

95%

 D

99%

Ans.
C
Explanation:
If the distribution of observations is bell-shaped, then even more can be said about the percentage of observations that lay between the mean and ± 2 standard deviations. For a bell-shaped distribution, approximately:
  • 67% of the observations lie between the mean ± 1 standard deviation
  • 95% of the observations lie between the mean ± 2 standard deviations
  • 99.7% of the observations lie between the mean ± 3 standard deviations
Ref: Dawson B., Trapp R.G. (2004). Chapter 3. Summarizing Data & Presenting Data in Tables & Graphs. In B. Dawson, R.G. Trapp (Eds), Basic & Clinical Biostatistics, 4e.

 


Q. 4

A normal distribution curve depends on – 

 A

Mean and Sample size

 B

Range and Sample Size

 C

Mean and Standard deviation

 D

Mean and median

Ans.
C
Explanation:

Ans. is ‘c’ i.e., Mean and standard deviation 

o Normal distribution curve is based on mean and standard deviation


Q. 5

Shape of normal distribution curve‑

 A

J shape

 B

U shape

 C

Bell shape

 D

None

Ans.
C
Explanation:

Ans. is ‘c’ i.e., Bell shape 

o Standard normal curve (Gaussian distribution) is bell shape curve.


Q. 6

Regarding the normal curve, true is/are-

 A

Both limbs of the curve touch the baseline

 B

Curve is bilaterally symmetrical

 C

There is a skew to the right

 D

There is a skew to the left

Ans.
B
Explanation:

Ans. is ‘b’ i.e., Curve is bilaterally symmetrical 

o Confidence limit of normal curve can never be 100%; therefore, limbs of curve never touch the baseline.

o Mean, Median and mode all coincide —> No skew.


Q. 7

Normal curve –

 A

Distribution of data is symmetrical

 B

Mean > Mode

 C

Mode > Mean

 D

Median > Mean

Ans.
A
Explanation:

Ans. is ‘a’ i.e., Distribution of data is symmetrical 

o In standard normal curve data is distributed symmetrically on either side of central value.

o Mean = Median = mode = zero


Q. 8

Systolic BP of a group of persons follows normal distribution curve. The mean BP is 120. The values above 120 are –

 A

25%

 B

75%

 C

50%

 D

100%

Ans.
C
Explanation:

Ans. is c i.e., 50%


Q. 9

In a group of 100 children, the weight of a child is 15 kg. The standard error is 1.5 kg. Which one of the following is TRUE –

 A

95% of all children weigh between 12 and 18 kg

 B

95% of all children weigh between 13.5 and 16.5 kg

 C

99% of all children weigh between 12 and 18 kg

 D

99% of all children weigh between 13.5 and 16.5kg

Ans.
A
Explanation:

Ans. is ‘a’ i.e., 95% of all children weight between 12 and 18 kg 

o Here the examinor himself has given us the valve of standard error = 1.5

o So, we can directly apply sample data to population.

o 95% of data will be covered by 2 standard error = 15 ± 2 SE =12 ± 3

= 12 to 18


Q. 10 Standard error of mean indicates –
 A

Dispersion

 B

Distribution

 C

Variation

 D

a and c

Ans.
D
Explanation:

Ans. is ‘a’ i.e., Dispersion; ‘c’ Variation

Standard error of mean

  • It is simply referred to as standard error.

o If we measure a sample from a wider population, then the mean of the sample will be an approximation of the total population mean.

  • But how accurate is this ?

o The answer of this question is to calculate standard error of mean :

o If we take multiple samples from a wide population, and measure the mean of each sample, we will find that every sample has different mean.

o If we make a frequency distribution of all these means (means of every sample), we will find the distribution of these means is normal Gaussian distribution.

o The mean of all these sample means (mean of every sample) will be same as the population mean.

Standard error of mean is the standard deviation of the mean of sample means, and thus gives a measure of their spread.


Q. 11

Standard errors of mean, all are true except

 A Increases with increased number of samples
 B

Based on normal distribution curve

 C

Measure the confidence limit

 D

Standard deviation

Ans.
A
Explanation:

Ans. is ‘a’ i.e., Increase with sample size increase 


Q. 12

While calculating the incubation period for measles in a group of 25 children, deviation is 2 and the mean incubation period is 8 days. Calculate the standard error –

 A

0.4

 B

1

 C

0.5

 D

2

Ans.
A
Explanation:

Ans. is ‘a’ i.e., 0.4


Q. 13

Estimated mean Hemoglobin (I-lb) of 100 women is 10g%. Standard deviation (a) is lgm%. Standard error of estimate will be –

 A

0.001

 B

1.0

 C

10.0

 D

0.1

Ans.
D
Explanation:

Ans. is ‘d’ i.e., 0.1 

o Standard error of mean is calculated as Standard Deviation/ VT1; where ‘n’ is the total number of values within the sample. Thus the standard error of mean hemoglobin from the above sample would be (1.0/ Vioo ) or 1/10 or 0.1.


Q. 14

For a negatively skewed data mean will be

 A

Less than median

 B

More than median

 C

Equal to median

 D

One

Ans.
A
Explanation:

Ans. is ‘a’ i.e., Less than median

  • Sidedness of the skewed distribution is towards the side of tail. For example right sided skewed deviation means the tail is towards the right.

Facts to remember the relation between mean, media & mode (see above figure) :-

i)    Mean is right of the median under right skew, and left of the median under left skew.

ii)  Mode is left of the median under right skew, and right of the median under left skew.


Q. 15 In a Left skewed curve, true statement is?
 A

Mean = Median

 B

Mean < Mode

 C

Mean>Mode

 D

Mean = Mode

Ans.
B
Explanation:

Ans. is ‘b’ i.e., Mean < Mode 


Q. 16

A non-sysmmetrical frequency distribution is known as –

 A

Normal distribution

 B

Skewed distribution

 C

Cumulative frequency distribution

 D

None of the above

Ans.
B
Explanation:

Ans. is ‘b’ i.e., Skewed distribution 


Q. 17

In a normal distribution curve, the true statement is:

March 2011, March 2013

 A

Mean = standard deviation

 B

Median = standard deviation

 C

Mean = 2 median

 D

Mean = mode

Ans.
D
Explanation:

Ans. D: Mean = Mode

In a normal distribution curve, mean, mode and median coincide

Normal distribution

  • It describes real world situations based on study results.
  • It is used for continuous quantitative variables.
  • It has an infinite range.
  • It is the distribution that is normally seen.
  • Although it is called “Normal” it applies to most biomedical measurements specially with big number of observations.
  • It is the most important tool in analysis of epidemiological and research data.
  • Has a Bell Shape Curve and is Symmetric
  • It is Symmetric around a central axis (the mean)
  • The halves of the curve are the same (mirror images)
  • Mean = Median = Mode determine the location of the curve
  • The total area under the curve is 1 (or 100%)
  • Distinguishing features of normal distribution
  • The mean ± 1 standard deviation covers 68% of the area under the curve (68% of cases)
  • The mean ± 2 standard deviation covers 95% of the area under the curve (95% of cases)
  • The mean ± 3 standard deviation covers 99.7% of the area under the curve (almost all cases)

Q. 18 The type of distribution, if mean 209, median 196, and mode 135 ‑
 A Standard curve
 B

Positively skewed

 C

Negatively skewed

 D

J-shaped

Ans.
B
Explanation:

Ans. is ‘b’ i.e., Positively skewed

In question, mean > median > mode → Feature of positively skewed deviation.


Q. 19

In positively skewed deviation ‑

 A

Mean = Median = Mode

 B

Mean > Medians > Mode

 C

Mode > Median > Mean

 D

None of the above

Ans.
B
Explanation:

Ans. is ‘b’ i.e., Mean > Medians > Mode


Q. 20

Identify the Distribution Shown.

 A

Normal Distribution

 B

Right Skewed Distribution

 C

Left Skewed Distribution

 D

Poisonn’s Distribution

Ans.
B
Explanation:

Ans:B.)Right Skewed Distribution

Normal Distribution Curve 

  • A histogram is the graphical representation of quantitative data .
  • It is used for continuous quantitative variables like systolic BP, height, weight etc.
  • It has an infinite range.
  • Characteristics of a Normal Curve
  • It is bell shaped
  • It is symmetrical bilaterally.
  • Total area of the curve is 1; its mean is zero; and its standard deviation is 1.
  • Mean, mode and median coincide and = 0
  • It has two inflictions at the points where the curve changes from convexity to concavity
  • Mean ± 1 SD includes 68.27% of observations
  • Mean ± 2 SD will include 95% of the values and
  • Mean ± 3 SD will include 99.5% of observations.

Skew distribution.
Skewed to left (negatively skewed)

  • A left-skewed distribution has a long left tail. 
  • The mean is also to the left of the peak.
  • Median>mean.

Skewed to Right (Positively skewed)

  • A right-skewed distribution has a long right tail.
  •  The mean is also to the right of the peak.
  • Median<mean.

Poisson distribution .

  • Limiting form of binominal distribution when probability  of   success  is   closer   to   zero   and numbers of trials are infinite. Mean=variance.

Q. 21 The following box plot shows the distribution of three sets of data around the mean. What is the correct sequence of inference from this box plot?
 A

1-Normal distribution, 2-Positive skewed, 3-Negative skewed

 B

1-Normal distribution, 2-Negative skewed, 3-Positive skewed

 C

1-Negative skewed, 2-Positive skewed, 3-Normal distribution

 D

I -Positive skewed, 2-Normal distribution, 3-Negative skewed

Ans.
B
Explanation:

Ans: B. 1-Normal distribution, 2-Negative skewed, 3-Positive skewed

Positive or negative skewed data:

  • Defined by the direction of the tail, i.e. direction of the least frequency values.
  • Similarly in this box plot, we can see that the data is equally distributed on either side of the mean box in Plot (1).
  • In Plot (2), the median is towards the higher side and most values are distributed towards the higher side hence it is negatively skewed.
  • Hence, vice versa for Plot (3).

Q. 22

Area under Normal curve with ±1 SD:

 A 0.68
 B

0.17

 C

0.12

 D

0.34

Ans.
A
Explanation:

Answer- A. 0.68

The area under the Normal curve with ± 1 SD is 0.68.