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Image Based Question-67099

Question

Diagnose the underlying condition due to electrolyte disturbance.

A. Hyperkalemia

B. Hypokalemia

C. Hypercalcemia

D. Hypocalcemia

 

Show Answer

Correct Answer » A

Explanation

Ans: A. Hyperkalemia

This ECG image displays many of the features of hyperkalaemia:

  • Prolonged PR interval.
  • Broad, bizarre QRS complexes — these merge with both the preceding P wave and subsequent T wave.
  • Peaked T waves.

Hyperkalemia

  • Potassium is vital for regulating the normal electrical activity of the heart.
  • Increased extracellular potassium reduces myocardial excitability, with depression of both pacemaking and conducting tissues.
  • Progressively worsening hyperkalaemia leads to suppression of impulse generation by the SA node and reduced conduction by the AV node and His-Purkinje system, resulting in bradycardia and conduction blocks and ultimately cardiac arrest.

Classification

  • Hyperkalaemia is defined as a potassium level > 5.5 mEq/L
  • Moderate hyperkalaemia is a serum potassium > 6.0 mEq/L
  • Severe hyperkalaemia is a serum potassium > 7.0 mE/L

Effects of Hyperkalemia on ECG

Serum potassium > 5.5 mEq/L is associated with repolarization abnormalities:

  • Peaked T waves (usually the earliest sign of hyperkalaemia)
  • Serum potassium > 6.5 mEq/L is associated with progressive paralysis of the atria:
  • P wave widens and flattens
  • PR segment lengthens
  • P waves eventually disappear

Serum potassium > 7.0 mEq/L is associated with conduction abnormalities and bradycardia:

  • Prolonged QRS interval with bizarre QRS morphology
  • High-grade AV block with slow junctional and ventricular escape rhythms
  • Any kind of conduction block (bundle branch blocks, fascicular blocks)
  • Sinus bradycardia or slow AF
  • Development of a sine wave appearance (a pre-terminal rhythm)

Serum potassium level of > 9.0 mEq/L causes cardiac arrest due to:

  • Asystole
  • Ventricular fibrillation
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